To create tetration, it is better that we work with a commutative exponentiation
$$x\wedge y:=x^{\ln y}.$$
With this definition, tetration would be the solution to the functional equation
$$f(ab)=f(a)\wedge f(b)={f(a)}^{\ln f(b)}$$
Properties
1. \(f(1)=e\)
2.
$$\ln f(\frac{1}{x})=\frac{1}{\ln f(x)},$$
so
3. \(\ln f(-1)=\pm 1\)
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