On one hand
$$\textbf{p}=\frac{1}{c^2}\int_{V}\textbf{S}d\tau,$$
on the other hand
$$\textbf{p}=\hbar\textbf{k}.$$
Not all waves are harmonic. So we must first find a way to generalize de Broglie's relation to all waves. One approach is to work with $$\Psi=e^{i(\textbf{k}\cdot\textbf{x}-\omega t)},$$ yielding $$\textbf{k}=-i\frac{\nabla\Psi}{\Psi}$$ on which I have written extensively. The disadvantage of this approach is that imaginary unit \(i\) shows up, which is not ideal.
Another is to work with $$\Psi=\sin(\textbf{k}\cdot\textbf{x}-\omega t),$$ which yields
$$\boxed{\textbf{k}=\frac{\nabla\Psi}{\sqrt{1-\Psi^2}}}$$
Advantages
- No \(i\)
- Works for vector (and tensor) \(\Psi\)
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