Sunday, 10 December 2023

Jerk and Snap in the Universe

 $$R=\sqrt[3]{\frac{GM}{H_0^2}} $$

$$R=\sqrt[4]{\frac{cGM}{H_0^3}}$$

$$\frac{dF}{da}=m$$

$$\frac{dF}{da}\frac{da}{d\alpha}=m=\frac{dF}{da}\frac{j}{\sqrt{j^2+j_0^2}}$$

$$j_0=\zeta cH_0^3$$


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