Wave equation of a material particle

 $$E=\frac{1}{2}m\textbf{v}^2 + \frac{1}{2}I\boldsymbol{\omega}^2$$

If we assume

$$\textbf{v}=\textbf{v}(x,t),$$ $$\boldsymbol{\omega}=\boldsymbol{\omega}(x,t),$$

then

$$A\frac{\partial\textbf{v}}{\partial x}=-I\frac{\partial\boldsymbol{\omega}}{\partial t},$$ and $$B\frac{\partial\boldsymbol{\omega}}{\partial x}=-m\frac{\partial\textbf{v}}{\partial t},$$ we arrive at

$$\boxed{\frac{mI}{AB}\frac{\partial^2\textbf{v}}{\partial t^2}= \frac{\partial^2\textbf{v}}{\partial x^2}}$$